If Michael Jordan Has A Vertical Leap Of 1.29m., Then What Is His Takeoff Speed And His Hang Time (Total Time To Move Upwards To The Peak And Then Ret

if michael jordan has a vertical leap of 1.29m., then what is his takeoff speed and his hang time (total time to move upwards to the peak and then return to the ground)

 

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Problem:

if michael jordan has a vertical leap of 1.29m., then what is his takeoff speed and his hang time (total time to move upwards to the peak and then return to the ground)

Given Data:

d (distance) =  1.29 m

Vf (final velocity) = 0 m/s (maximum height)

a  (acceleration) = -9.8 m/s² (going up)

Vi (initial velocity) = ? unknown

Solution:

we can use the formula Vi = - 2ad since Vf = 0 m/s

Vi =√ - 2ad

   =√ - 2 ×  -9.8 m/s²  ×  1.29 m

   = √  19.6 m/s² × 1.29 m

   = √ 25.284 m²/s²

   = 5.028 m/s

Note: The time going up until it reaches the maximum height is equal to time from the top to return to the ground.

to determine the total hang time,  we must multiply the time going up by 2.

Solve for time going up.

t = Vf - Vi / a

 = 0 m/s - 5.028 m/s / -9.8 m/s²

 = - 5.028 m/s / -9.8 m/s²

 = 0.513 seconds

total hang time = 0.513 s × 2 = 1.026 seconds

total hang time = 1.026 seconds